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#math
<mahamoti> id rather be in an active associated forum :)
<asphyxia> I have chi-squared-table if thats what you like
<asphyxia> I can look things up
<mahamoti> asphyxia: well, im trying to figure out what exactly a chi-squared table is.
<asphyxia> I dont know if that is what you seek though :)
<mahamoti> is it the pdf, or cdf, or the chi-squared distribution?
<mahamoti> i want to apply the chi-squared test to some data
<mahamoti> i also want to apply the runs test, and i have computed the r-statistic, but im not quite sure how to use/interpret this statistic
<asphyxia> mahamoti: it says in my statistics and probability book: chi-squared-distribution - for every p and f, x is given as the P(X > x) = p, if the stochastic variable X is chi-squared distributed with f freedom degrees
<asphyxia> I dont know how to translate freedom degrees.
<mahamoti> i know what they mean by degrees of freedom
<asphyxia> ok
<mahamoti> i can read about the chi-squared distribution on wikipedia but im just not quite sure how to use it in the chi-squared test
<asphyxia> ehm, sec
<asphyxia> well, I'm trying to interpret my book, but I only took statistics and prob 101
<asphyxia> so I actually dont remember anything
<mahamoti> oh well, thanks
<asphyxia> plus, my textbooks is in danish, and I have a hard time explaining some of the words, as it is 6:29 am here
<gzl> asphyxia: you were looking for me?
<asphyxia> yeah
<asphyxia> It's about those dang cycles again. I cant seem to grasp how I can construct a cycle consisting of to elements (x_1 x_2) by the product (a x_1)(a x_2)(a x_1)
<asphyxia> there is an example, in which t = (1,2) = (1 3)(2 3)(1 3) = (2 3)(1 3)(2 3)
<asphyxia> I just cant see, how 3 is kind of pushed out of the transposition
<gzl> it's because for any transposition t, t^2 = 1
<gzl> if you just apply the same transposition twice, nothing happens. it swaps the two things back
<gzl> all you have to do to see how it works is to see what happens when you apply those functions to 3
<gzl> you should find that 3 gets sent to 1 (or 2), then 1 (or 2) gets sent back to 3
<gzl> so 3 doesn't go anywhere
<asphyxia> oh, cause transposes are their own inverses.
<asphyxia> gzl: Ah, and that makes 3 a fixed point for t.
<gzl> yeah. though just because there are two of the same guy doesn't mean it always happens. see (2 3)(1 2)(2 3)
<asphyxia> gzl: ehm, still not quite following; (1 3)(2 3)(1 3) - 1 to 3, 3 to 2, then what?
<gzl> where does 3 go?
<asphyxia> which of them?
<gzl> in mine, I don't know why you changed it
<asphyxia> Im totally confused now. I think I give up for now.
<gzl> what?
<gzl> forget the question I just asked. do you get the answer to YOUR question?
<gzl> why 3 disappears
<asphyxia> no.
<gzl> so what was this?
<gzl> 00:41 (asphyxia) oh, cause transposes are their own inverses.
<gzl> 00:41 (asphyxia) gzl: Ah, and that makes 3 a fixed point for t.
<asphyxia> Well, I am kind of able to pinpoint what happens. Only I cant understand why
<gzl> look. there is one and only one thing you need to do. if you have something like (1 3)(2 3)(1 3), and your book says it's equal to (1 2), and you don't see why, all you have to do is apply it to 1, 2, and 3, and see what happens.
<gzl> if you find that 1 goes to 2, 2 goes to 1, and 3 goes to 3, that's the end of it.
<asphyxia> Ok. But the way I see it, is that 1 goes to 3 in the first parantheses
<gzl> as long as you're able to evaluate these functions, there really shouldn't be a problem
<asphyxia> Then 3 goes to 2 in the next. and then I dont know what happens
<gzl> that's all that happens!
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