Olathe | Nope. |

anubiss | sub question to that onw |

Olathe | I know Mathematica a bit, but not really TeX :) |

anubiss | i have to find the equation for the curve that satisfies the initial condition: which is passing by the point (-3,4) |

ailndx | oh cool, didnt knew mathematica could do that |

TRWBW | anubiss: so you are solving for C. or -C, whatever. |

anubiss | the answer in the book is quite weird let me try first |

TRWBW | anubiss: what was it? y=-1/(x^2-C)? then 4=-1/(9-C), 9-C=-1/4, C=37/4, y=-1/(x^2-37/4) |

anubiss | oh i tried to arrange the term and isolate C on one side first |

Xerroz | can anyone recommend a online tutorial for Trigonometry? |

anubiss | is that wrong ? |

TRWBW | anubiss: did you get the right answer? |

anubiss | i do variables switch first then plug in numbers i didnt get yet ;/ |

Olathe | xerroz: I think purplemath and sosmath have one. |

anubiss | i have something weird see: x^2y + Cy = -1 then i block here ...isolating the C i still got some algebra problems |

TRWBW | anubiss: C=-(1+x^2y)/y=-(1+9*4)/4=-37/4 anubiss: Cy=-1 - x^2y=-(1+x^y), divide by y, C=-(1+x^2y)/y=-(1+9*4)/4=-37/4 |

anubiss | thats nice to write it all, i can work it on my own, and see my mistaks |

TRWBW | anubiss: i'm kinda tired, i'm sorta in just give the answer mode |

anubiss | but im serious |

TRWBW | anubiss: k, hope that helped. gl |

anubiss | thanks ! |

Kizak | Hello Everyone |

Olathe | Hi. |

Kizak | somewhere here smart with math I hope? :P |

ailndx | whats the size of the empty set, 0 or 1? |

Olathe | Nope. We're all here to get help, too. ailndx: Zero. |

ailndx | ok, can a subset be same as the original set? |

anubiss | Kizak: sorry i was the last one to receive help, 1 minute ago |

TRWBW | ailndx: the original set is a subset of the original set |

Olathe | ailndx: Yep, if you don't mean proper subset. |