demio | I've constrained z to 0 <= z <= 1 But I'm having a hard time figuring out the constraint to y |

zaphyBeeble | ask _|||_ :) he knows more math than me :) |

_llll_ | what does "figuring out the constraint to y" mean? |

jkjk | I read that to signals (same kinds of frequencies, same amount, but different order) have the same fourier spectrum (kinda makes sense) BUT: How does the inverse fourier transform "know" which signal to restore ? |

demio | for the integral |

jkjk | *to two |

zaphyBeeble | im out of touch with stuff |

demio | i need to know the boundaries of the volume integral |

_llll_ | see, now you are making more sense "y>=0" gives you one of the y-limits, yes? |

demio | yea now I need to figure out the upper bound in terms of z |

_llll_ | you need to draw a picture of your solid |

zaphyBeeble | yeah but apprently he doesnt... the constraints canbe determined from the z equation |

_llll_ | the easiest way is to draw it i reckon, anyway |

zaphyBeeble | yeah i guess |

demio | but I need to know how to get the constraint from the equations only |

zaphyBeeble | they dont let u take those damn plotters to school damn it |

demio | :P |

zaphyBeeble | 0 <= z <= 1 - (sqrt[x^2+y^2] - 1)^2 |

_llll_ | draw a picture. with a pencil and paper |

demio | .. |

_llll_ | or use your brain |

demio | I can't rely on drawing |

_llll_ | oh well |

Defty | using brain is wasting neurons unless you're already good at .. drawing in your head ,p |

demio | god damned fubini :/ |

zaphyBeeble | too bad dont solve something you cant visualize :) well he previously wrote: 0 <= z <= 1 - (sqrt[x^2-y^2] - 1)^2 that blew me up :) |

marltu | % 2+2 mbot dead? damn |