#math - Sun 8 Apr 2007 between 00:11 and 00:25

NY Lost Funds



holsthehe
matlab is the best calculator you have
Menkaurei found one. TTCalc. its quite easy to handle and enough for my calculations. that other ones are much to hard for me. i do just a few simple calculations. :)
1-(48/50)*(47/49)*(46/48)*(45/47)*(44/46)=0.191836734693877551020408163
so thats my calculation. but looks like ~20%
zoomzoomhay
Menkauremy poker programm told me ~12%. mmh is this calculation correct?
KasadkadFor what?
Menkaurehttp://pastebin.ca/429083
this calculation of possibilty for a texas hold em poker game
this was my first calculation
then someone told me to do it that way
1-(48/50)*(47/49)*(46/48)*(45/47)*(44/46)=0.191836734693877551020408163
KasadkadI don't really get your question
Oh
If you have a pair already, what's the probability you get a card to make it three of a kind
?
Menkaureyes
Chewie[]So the probability of one of those 5 cards being an ace.
If you have 2 in your hand.
Menkaurei have a programm wich calculate every option. but i am not sure if it is working correct and want to know how to calculate that
yes
Chewie[]These aren't independent events, so I don't think you can just add.
(each card of the 5 being drawn that is.. Those are not independent.)
KasadkadWhy is it not just 2/50?
Chewie[]Well it migh tbe.
I'm not sure.
KasadkadI don't know how the game works
Chewie[]It's gonna be the number of ways to have an ace divided by the number of ways you can draw 5 cards out of the 50.
KasadkadYou have two cards, and then you get another card?
I mean
Chewie[]Say you have 2 aces in your hand. You take 5 cards randomly from the deck and lay them on the table.
So the deck will have 45 left, 5 will be on the table, 2 in your hand.
Menkaureyes
Chewie[]Menkaure: You want the probability of having either 3 or 4 aces out, right?
Or *only* 3 and not 4? :-P
KasadkadOh
Menkaure3 is interesting
Kasadkad*sigh8
Menkaure4 is about ~1%

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NY Lost Funds