sumpt | anyone have a site showing the derivation of the partial sum formula for an arithmetic series? |

Ransom | i cant see how you are getting x alone |

medfly | Ransom: 7*3.5*m / x = 1 |

Ransom | meh i gotta draw it i dont get it.. |

Squall` | for the first 4 terms of Gamma(1), I got lim k-> infinity e^-t (x + log t / (2 * 1!) (x-1)^2 + log ^2 t/(3 * 2!) (x-1)^3 + log ^ 3 t / (4 * 3!) (x-1)^4) from k to 0, but it doesn't seem like that would converge. Did I do something wrong? |

TRWBW | Squall`: no idea, are you doing Gamma(1+t)? |

Squall` | you mean Gamma(1, t)? |

TRWBW | well you got a t and and x in there and a k too, not sure what you are saying |

Squall` | okay, let me backtrack a bit oh ffs I integrated with respect to the wrong variable ahhhh all that work, wasted man, that's depressing |

Ransom | oh okay i figured it out i was thinking recipocal so do 7m/x * x/7m but x/1... |

jamisnemo | I've been trying to solve a differential equation but I can't find the answer anywhere. I need to find a general solution to x^2y''+7xy'+8y = 0 but I do not have a solution to the dif eq to use reduction of order could anyone help me out? |

Squall` | *sniff sniff* at least it erased cleanly |

Kasadkad | jamisnemo: Isn't that one of those where the substitution x = e^t helps? |

jamisnemo | it may be... I'll try that out now my head is all lost on this now |

Squall` | What kind of sadist makes x a constant? |

BrendanM | haha |

Kasadkad | It's not a constant, it's a change of variable http://en.wikipedia.org/wiki/Cauchy-Euler_equation |

Squall` | I'm not talking about his problem. I'm talking about mine haha |

jamisnemo | :P |

Kasadkad | Ah |

jamisnemo | I'll walk through it again at least I have a better idea as to where to start |

Squall` | I wasted like an hour of weird series expansion and integration because I integrated in respect to x, which was a CONSTANT!!!!! AHH!!! |

medfly | i feel your pain |

NIKEDUNKLOW | Squall` chin up lil buddy. |

Squall` | I mean, it IS a variable, it's just constant in this expression :( |

jamisnemo | Kasadkad: Thank you so much! That does work! Thankyouthankyouthankyou! |

Kasadkad | Sure |