#math - Thu 26 Apr 2007 between 02:08 and 02:19

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gtpif dg/dt = 0 then df/dg DNE that's all
I acn prove to you that f is a differentiable function of f from the equation he gave me
f is a differentiable function of g*
f=0 g=0
sorry
df/dt=0 dg/dt=0
so that takes care of the "exception"
Kirynhey whats a vertex perpendicular
TRWBWKiryn: is that the start of a joke? i don't know, what's a vertex perpendicular...
Kirynerr i meant perpendicular
gtp@jinc there's an infinite set of solutions
mbotMaybe you meant: join kind
Kirynsorry i copied and pasted it from a tutorial
TRWBWKiryn: there is a vertex bisector, a line that bisects the angle at a vertex of a polygon
KirynTRWBW, I just meant perpendicular. not vertex perpendicular
gtpdf/dg = (cos t + b)/ (a - sin t), that's all you can get, there's an infinite set of functions of f and g various forms
TRWBWKiryn: perpendicular to a line is another line that meets it at right angles.
Kiryn: a more precise definition depends on the type of geometry you are doing
demio% D [Arctan[x/y], x]
mbotdemio: Derivative[1][Arctan][x/y]/y
KirynTRWBW, http://www.riemers.net/eng/Tutorials/XNA/Csharp/Series1/Lighting_basics.php
demiowtf
Kirynthats where im reading about it
demio% D [Atan[x/y], x]
mbotdemio: Derivative[1][Atan][x/y]/y
demio>_>
% D [Arctan[x/y], x]
mbotdemio: Derivative[1][Arctan][x/y]/y
gtpdemio derivative of arctan(x) is 1/(1+x^2)
TRWBWKiryn: do you know differential geometry?
Steve|Officedemio: http://www.brainyquote.com/quotes/quotes/a/alberteins133991.html
demiowhat about arctan(x/y)
Kiryni have no idea what that means
demiodx
gtpso derivative of artan(x/y) is (1/(1+x^2))*(1/y)
TRWBWKiryn: how about vector calculus?
gtpchain rule
opps
Kirynnever did calculus
TRWBWKiryn: linear algebra?

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