## #math - Wed 25 Apr 2007 between 02:32 and 02:38

### NY Lost Funds

 timur welcome. good luck _kmh_ sniper89 : but it is not a cotangens value sniper89 no, it is notit's just _kmh_ ctg maps degrees to real numbers Kiryn anyone know if there is a program that can emulat a plane graph? lik what a graphing book is _kmh_ so the result cannot be in degrees sniper89 if a point lies in the 2nd quarter of the coord value, it means x will surely be negative, and y will be positive, rightand ctg a = x/yI need to use that and maybe r = sqrt(x^2 + y^2) to solve it _kmh_ to solve what ? sumpt ctg = ? sniper89 errfind the ctg 150*... _kmh_ i probably missed the earlier discussion - what is the actual problem ? sniper89 omagawdUsing the trigonometrical functions' definitions, find: ctg 150* _kmh_ well that cos (150)/sin(150) sniper89 cos a = x/rsin a = y/r sumpt what is ctg? sniper89 what do you mean, sumpt timur and you could consider r = 1 sumpt what does it stand for? sniper89 cotangens _kmh_ and cos(150)=-cos(30) sniper89 timur: consider? sumpt wouldn't that be represented by cot? sniper89 I don't think so... sumpt that's how my two books represent it, but ok timur well, r doesn't matter if you're figuring out sin, cos, tan, cot, etc, because it's the ratio that matters sniper89 ohbut still I don y xo dam timur do you know cos 30, sin 30? sniper89 *but still I don't know what y, x and ctg 150 are _kmh_ sin(150)=sin(30)timur : for that you can use a triangle timur that's where I was going with it ;p _kmh_ take a equilateral triangle with its height