#math - Mon 23 Apr 2007 between 00:00 and 00:07

NY Lost Funds



moeSizlakmore power to you i guess
centrxheh
noway-TRWBW, and we can assume the bijection because ?
Tarantulafudgehow would I write x-3y^2+4y+1 in standard form?
TRWBWnoway-: it's proof by contradiction
Tarantulafudgeoops
x=-3y^2+4y+1
ach
x3y^2+4y+1
nargTarantulafudge: order them by exponent degree
TRWBWnoway-: just prove this given any map f:A->P(A), there is an element of P(A) that isn't in the image of f. that implies that no bijection can exist.
noway-TRWBW, the statement said there is no injection from f: P(A) -> A
Tarantulafudgex=3y^2+4y+1
noway-ok
Tarantulafudgenarg: they are
narg: I think
OlatheTarantulafudge: You mean y = ... ?
TarantulafudgeOlathe: no this is a horizontal parabola
nargTarantulafudge: is this a quadratic standard form your after?
ah
Tarantulafudgesorry standard form is x=a(y-k)^2+h
OlatheTarantulafudge: Complete the square, I guess.
TarantulafudgeOlathe: how lol
Olathe: I mean I know how, but it doesn't look easy on this problem
Olathe(y - k)^2 = y^2 - 2ky + k^2, right ?
So, you have 3(y^2 + 4/3y + 1). k is 4/6.
Well, -2/3
Tarantulafudgehmm I haven't seen this equation before
OlatheSo, 3(y - 2/3)^2 + h, find h.
Bleh.
So, 3(y + 2/3)^2 + h, find h.
geckosen1toris a*(b*c) the same as (a*b)*c for matrixes?
Olathe% 3(y + 2/3)^2 + 5/9 //Expand
mbotOlathe: 17/9 + 4*y + 3*y^2
Olathe% 3(y + 2/3)^2 - 1/3 //Expand
mbotOlathe: 1 + 4*y + 3*y^2
OlatheThere.
geckosen1tor: Yep.
Tarantulafudgeinteresting
geckosen1torOlathe: sweet, so it's associative

Page: 2 9 16 23 30 37 

IrcArchive

NY Lost Funds