#math - Mon 23 Apr 2007 between 00:00 and 00:07

NY Lost Funds

 moeSizlak more power to you i guess centrx heh noway- TRWBW, and we can assume the bijection because ? Tarantulafudge how would I write x-3y^2+4y+1 in standard form? TRWBW noway-: it's proof by contradiction Tarantulafudge oopsx=-3y^2+4y+1achx3y^2+4y+1 narg Tarantulafudge: order them by exponent degree TRWBW noway-: just prove this given any map f:A->P(A), there is an element of P(A) that isn't in the image of f. that implies that no bijection can exist. noway- TRWBW, the statement said there is no injection from f: P(A) -> A Tarantulafudge x=3y^2+4y+1 noway- ok Tarantulafudge narg: they arenarg: I think Olathe Tarantulafudge: You mean y = ... ? Tarantulafudge Olathe: no this is a horizontal parabola narg Tarantulafudge: is this a quadratic standard form your after?ah Tarantulafudge sorry standard form is x=a(y-k)^2+h Olathe Tarantulafudge: Complete the square, I guess. Tarantulafudge Olathe: how lolOlathe: I mean I know how, but it doesn't look easy on this problem Olathe (y - k)^2 = y^2 - 2ky + k^2, right ?So, you have 3(y^2 + 4/3y + 1). k is 4/6.Well, -2/3 Tarantulafudge hmm I haven't seen this equation before Olathe So, 3(y - 2/3)^2 + h, find h.Bleh.So, 3(y + 2/3)^2 + h, find h. geckosen1tor is a*(b*c) the same as (a*b)*c for matrixes? Olathe % 3(y + 2/3)^2 + 5/9 //Expand mbot Olathe: 17/9 + 4*y + 3*y^2 Olathe % 3(y + 2/3)^2 - 1/3 //Expand mbot Olathe: 1 + 4*y + 3*y^2 Olathe There.geckosen1tor: Yep. Tarantulafudge interesting geckosen1tor Olathe: sweet, so it's associative