Olathe | Dinner is overrated. |

WILDSTYLE | The striploin I just ate was quite delicious actually. |

TRWBW | striploin? is that some foreign word for what? skirt steak? |

WILDSTYLE | skirt steak? |

Olathe | word ? |

Cale | http://en.wikipedia.org/wiki/Strip_steak |

moeSizlak | how in the everloving name of god do you integrate sin(x)*cos(x) ??????????? |

Cale | moeSizlak: -(1/2) cos(x)^2 |

WILDSTYLE | Thank you cale :) |

moeSizlak | what method is that/? |

TRWBW | moeSizlak: what's sin(a+b)? |

Olathe | moeSizlak: Substitution. |

kilimanjaro | let u = sin x, du = cos x dx |

TRWBW | moeSizlak: Cale is right, but you can do it more than one way |

moeSizlak | ok, so then you have the integral of u*du ? |

Olathe | Yes. |

moeSizlak | isnt that like ln u or comething? |

Olathe | Nope. |

kilimanjaro | 1/2 u^2 |

moeSizlak | what is it? oh yeah |

kilimanjaro | moeSizlak, you might want to practice finding derivatives |

moeSizlak | damn, im taking mth 411 probability theory, but i forgot all the lame integral bs from 1st semester |

kilimanjaro | at some point this should just be reflex what do you need integrals for? infinite probability spaces? |

moeSizlak | triple integrals actually |

TRWBW | moeSizlak: don't piss off the integral god |

moeSizlak | expected values of 3 random variables |

kilimanjaro | ahh continuous I guess |

Cale | You can play "guess the antiderivative", but when you get tired of that, substitution or integration by parts works well. |

moeSizlak | probability x<y<z (where x y z are r.v.;s) |

noway- | TRWBW, since f is a bijection then by def. there must be an a such that f(a) = p |

Cale | moeSizlak: For instance, you can use integration by parts -- integral of sin(x) cos(x) dx = integral of sin(x) sin'(x) dx = sin^2(x) - integral of sin'(x) sin(x) dx So 2 integral of sin(x) sin'(x) = sin^2(x) so integral of sin(x) sin'(x) = sin^2(x)/2 (up to a constant term) |

TRWBW | noway-: that's the whole point. it's a proof by contradiction. |

moeSizlak | what is the expected number of unique birthdays in a group of 25 random people? |

narg | lower than you'd think |