## #math - Thu 19 Apr 2007 between 00:02 and 00:29

### NY Lost Funds

 diseaser bah I still dont get it. Steve|Office ... What's not to get?d/dt |3t-4| = (|3t-4|/(3t-4))*3. Cecen You normally drop the function by a power of x, right? diseaser I get that.. I just can't connect some dots here to tie it all togetherCecen: yes Steve|Office diseaser: What aren't you getting? Cecen In this case, we can't just drop it by to the power of 0, so we have to divide it by the inside functionTaking x^2 and dropping it's exponent by 1 is the same as dividing by x diseaser ahhhhthat helps walczyk 4.8 A gun is located at the bottom of a hill of constant slope p. Show that the range of the measured up the slope of the hill is 2*v_0^2*cosa*sin(a-p)/(g*cos^2p) where a is the angel of elevation of hte gun, and the maximum value of the slope range is v_0^2/(g*(1+sinp)) Steve|Office That sentence doesn't make sense no matter which network you paste it in. diseaser Ahh so the critical value would be -4/3 in my caseactually -4/3, and 4/3 Steve|Office Why -4/3? diseaser because it would make the numerator 0, thus f(-4/3) = 0 ?I think3(|3t-4|/(3t-4)) Steve|Office -4/3*3 - 4 is not 0. diseaser no, but it would set the numerator of that equation to 0making the whole thing 0s/equation/expressioncrapno it wouldnt, would itI'm thinking |t|, not |3t-4|hargh, sorry man my mind is running on fumes here today jadenbane Hmmm TRWBW, I'm flunking on the proving that if a symmetric has two distinct eigenvalues, their eigenvectors are orthogonal. I suck. g35coupe what is a square of a graph G^2 SeveredCross What's G/ FatalError g35coupe, perhaps the graph obtained by squaring the adjacency matrix? (just a guess, mind you)I'm not familiar with that terminology walczyk Steve|Office why doesnt it make sense Steve|Office " Show that the range of the measured up the slope of the hill..." walczyk yeah thats how the book worded itits asking the range of the projective measured from the bottom of the hill to the impactas opposed to the x-axis jadenbane How do you prove that if a symmetric has two distinct eigenvalues, their eigenvectors are orthogonal n0dl hello. what would be the best approach to factor y = 2 - 15x + 9x^2 - x^3 ? WILDSTYLE Hi.