#math - Thu 19 Apr 2007 between 00:02 and 00:29

NY Lost Funds



diseaserbah I still dont get it.
Steve|Office... What's not to get?
d/dt |3t-4| = (|3t-4|/(3t-4))*3.
CecenYou normally drop the function by a power of x, right?
diseaserI get that.. I just can't connect some dots here to tie it all together
Cecen: yes
Steve|Officediseaser: What aren't you getting?
CecenIn this case, we can't just drop it by to the power of 0, so we have to divide it by the inside function
Taking x^2 and dropping it's exponent by 1 is the same as dividing by x
diseaserahhhh
that helps
walczyk4.8 A gun is located at the bottom of a hill of constant slope p. Show that the range of the measured up the slope of the hill is 2*v_0^2*cosa*sin(a-p)/(g*cos^2p) where a is the angel of elevation of hte gun, and the maximum value of the slope range is v_0^2/(g*(1+sinp))
Steve|OfficeThat sentence doesn't make sense no matter which network you paste it in.
diseaserAhh so the critical value would be -4/3 in my case
actually -4/3, and 4/3
Steve|OfficeWhy -4/3?
diseaserbecause it would make the numerator 0, thus f(-4/3) = 0 ?
I think
3(|3t-4|/(3t-4))
Steve|Office-4/3*3 - 4 is not 0.
diseaserno, but it would set the numerator of that equation to 0
making the whole thing 0
s/equation/expression
crap
no it wouldnt, would it
I'm thinking |t|, not |3t-4|
hargh, sorry man my mind is running on fumes here today
jadenbaneHmmm TRWBW, I'm flunking on the proving that if a symmetric has two distinct eigenvalues, their eigenvectors are orthogonal. I suck.
g35coupewhat is a square of a graph G^2
SeveredCrossWhat's G/
FatalErrorg35coupe, perhaps the graph obtained by squaring the adjacency matrix? (just a guess, mind you)
I'm not familiar with that terminology
walczykSteve|Office why doesnt it make sense
Steve|Office" Show that the range of the measured up the slope of the hill..."
walczykyeah thats how the book worded it
its asking the range of the projective measured from the bottom of the hill to the impact
as opposed to the x-axis
jadenbaneHow do you prove that if a symmetric has two distinct eigenvalues, their eigenvectors are orthogonal
n0dlhello. what would be the best approach to factor y = 2 - 15x + 9x^2 - x^3 ?
WILDSTYLEHi.

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NY Lost Funds