lesshaste | well ,,, I changed the lines to 3 320 120 55.92 (i.e. I removed the names) and I did scan(file = "scores.txt") but it doesn't seem to have loaded it in in a useful way anyone able to help ? |

TRWBW | lesshaste: this isn't really the channel for that. it's more for the theory than how to use a particular program. try something like #stats i'm guessing. |

lesshaste | sadly no such channel |

TRWBW | about as likely to get your answer here as in #klingon-speakers |

lesshaste | oh R is quite popular amongst mathematicians |

WILDSTYLE | R is alright. |

lesshaste | can I ask a question about the coupon collector's problem? |

WILDSTYLE | I'm kinda partial to C. |

lesshaste | WILDSTYLE: is that a joke? |

TRWBW | i tried R, but when back to using C and Fortran |

JabberWalkie | lesshaste: no you have to read the topic first |

TRWBW | lesshaste: no, for statistics it's a lot nicer to do it in a real programming language. it runs faster, you can get libraries with better algorithms, etc. |

Zanco-afIRC | Hello Everybody |

WILDSTYLE | hello. |

jadenbane | Does Sum (1, inf., 1/(n(n+1))) = 0 ? |

Mulder | jadenbane, no for starters, 1/2 is one of the terms you add so automatically, your sum is > 0 |

jadenbane | Haha, I should actually look at the numbers shouldn't I :P Sum (1, inf., 1/(n(n+1))) = Sum (1, inf., 1/n - 1/(n+1)) which makes me think there will be cancelation. |

Mulder | if you can decompose it into a partial fraction lik ethat you can telescope, and work out what the infinite sum is and and your final sum is probably something like 1 |

jadenbane | See, I'm not sure what telescoping is, since I only have a vague notion of ir. *it. |

Mulder | well, a series is just a seqeuence of partial fractions |

jadenbane | Oh, that sum will give 1/1 - 1/2 + 1/2 + 1/3 - 1/3 etc. |

Mulder | yes |

jadenbane | So yeah, I was hasty in guessing zero. I should have guessed one. |

Mulder | so s_n = 1 - 1/2 + 1/2 + 1/3 - 1/3 + ... - 1/(n-1) + 1/(n-1) - 1/n s_n = 1 + 1/n then if we take the limit of that, we get 1 since 1/n goes to 0 as n -> Infinity |