#math - Mon 5 Mar 2007 between 18:15 and 18:29



TRWBWdavidstrauss: how much experience do you have with saying non-sequitors?
davidstraussmerus: he said "the def. that I have just says it's a relation where each input is related to one and only one output"
that is defined as one-to-oneness
well
not quite
merusThat is not injectivity.
davidstraussTRWBW: cardinality theory has extensive coverage of functional mappings
it's used as a tool for proving set cardinality
brick_this is a pretty basic set theory into class so i'm guessing this doesn't involve complex cardinality
davidstraussset theory and cardinality are complementary studies
TRWBWbrick_: davidstrauss said something irrelevant, now he's going off on a tangent because he's embarassed. you can ignore him.
brick_s/into/intro. anyways, a relation between X and Y is just the cartesian product of them?
TRWBWbrick_: yes
thief_grrbrick_: no
davidstraussa relation is a *subset* of the cartesion product
thief_grrbrick_: it's a subset of the cartesian product
TRWBWdavidstrauss: true
brick_So we'd have say {(a,u), (b,u), (c,u)}?
TRWBWbrick_: that's it.
thief_grrbrick_: this is a relation which happens to be a function
brick_: while {(a, u)} is a relation which is not a function. unless you accept partial functions
lokiehey guys
brick_maybe it's just the notation that's confusing me: If the question says "find all functions from X to Y" would writing the set {(a,u), (b,u), (c,u)} be appropriate? Mayhaps i'm just used to writing functions as f(x)
davidstraussyes, that is acceptable notation
it's a finite relation, so the function it models has finite possibilities
lokieif i had tripple integral e^z dV, and i'm converting it into cylinderical coordinates, and i got: 0 <= r <= sqrt(5); 0 <= z <= 1+r^2; 0 <= t <= 2PI; t is theta btw. i now have: tripple integral with the bounds i just listed, e^zr dr dt dz, can i split it up into e^z dz (r dr) ( dt) and intgrate them all seperately and multiply the answers at the end?
davidstraussthus, you can list them all
TRWBWbrick_: you could stick and extra {} around it to make it the set containing just that.
davidstraussTRWBW: even better
TRWBWbrick_: f(x)=u is probably acceptable too, but given the level of the question, i suspect you are doing basic function theory, and they might want you to write it explicitly in terms of the definition
Defty% Solve[ 1/6*x + 3/2 == Sqrt[x], x]
mbotDefty: {{x -> 9}}
Defty% Solve[ D[1/6*x + 3/2,x] == D[Sqrt[x],x], x]
mbotDefty: {{x -> 9}}
lokiehm...why isn't that possible? I just attempted what I said above and i'm getting e^(1+r^2)-1 * 2PI * 5/2
TRWBWDefty: why don't you and mbot get a room?
Deftyi'm not sure how to ask her in private
lokieo its a female? hott
TRWBWDefty: you need to /identify yourself, then you can /msg mbot % 1+1
Deftymuse ex machina..

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