#math - Sat 24 Mar 2007 between 00:00 and 00:26

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klafkaif i consider S and all subsets of S, let S be an infinite set, and i want to check if intersection and union of elements form a ring, if i have 2 elements of S what would AND and OR even be
is S a power set?
so i have a set of sets?
Kasadkadklafka: S isn't a power set unless you say it's a power set
klafkawell all my teacher said was, "let S and all subsets of S, let S be an infinite set" the only way AND and OR make sense is if S is a set of sets, or like binary strings?
KasadkadAh
It probably has to be a power set
omgomglolCould anyone check my work for this integral? http://www.mathbin.net/9433 I'm having a bit of trouble
qqexcheck parentheses/brackets in your equation omgomglol
klafkathis is really confusing, i was suppose to show that AND and OR do not form a ring but...they do! they are closed and they meet all 6 of the requirements
omgomglolok, should be fixed
Mr_Awesomehow can LU decomposition be used to find the inverse of a matrix?
Kasadkadklafka: with what set?
klafkathe power set of an infinite set
Kasadkadklafka: additive inverses??
action|DARK_MAN| dos damas que no tengan con kien ir a carretiar mandar pv2 ahora ya !!!!!!!!!!!! faltan dos damas!!!!
|DARK_MAN|dos damas que no tengan con kien ir a carretiar mandar pv2 ahora ya !!!!!!!!!!!! faltan dos damas!!!!
klafkaA ^ A
= {o}
KasadkadUh
A intersect A = A
klafkaooh
oh duh
um A AND A-complement = {0}
WILDSTYLEHi.
Kasadkadklafka: what about additive identity?
Hi
Well
klafkaidentity is A + e = A, so A AND A = A
oh but it has to be true for all
doesn't it
KasadkadFirst off: you're taking intersect as addition and union as multiplication?
Yes
qqexomgomglol: the integrand is missing a bracket
klafkaum sec
qqexomgomglo ah nm i see you fixed it
klafkaum A ^ S = A
action|DARK_MAN| dos damas que no tengan con kien ir a carretiar mandar pv2 ahora ya !!!!!!!!!!!! faltan dos damas!!!!
|DARK_MAN|dos damas que no tengan con kien ir a carretiar mandar pv2 ahora ya !!!!!!!!!!!! faltan dos damas!!!!
klafkawell if S is a powerset, then it contains itself? wait it can't contain itself?
can it
KasadkadNo

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