#math - Fri 23 Mar 2007 between 14:12 and 14:33

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doserjand remove the break statement
then it gives you the "primes" starting from 1
(ignoring the fact that 1 isn't a prime)
rsa_md5oops sorry..totally overlooked that fact
and thanks a lot for that help
TRWBWAtraeyu: you can use mathbin too. if you want to you can steal the gif after it's been generated.
qqexLet X be the space obtained by identifying two interior points of D^2 (i.e. X=D^2/(p~q)). find the fundamental group of X.
deltaAtraeyu, http://directory.fsf.org/htmlatex.html ?
rsa_md5doserj:yeah, now it works, but I dint remove the break statement anyways
doserjyou can leave the break statement, yes
toedqqex: I don't understand what points are being identified
qqextoed: any two interior points.
deltaqqex, it looks like S^1 to me.
toedoh
qqexif they were boundary points, i see what to do. it would be Z.
i'm unsure about the "interior" part
deltaqqex, I'm seeing 2 cones over a S^1 base, with 2 pairs of points identified, the vertices and 1 point on each base circle. This seems homotopic to a circle.
qqexi see an elongated hemisphere, pinched above the equator. perhaps delta yours is the same.
_llll_i think the space is a retract of the straight-line joining the two points
err, or that one is a retract of it, rather
deltaqqex, out of curiosity, the question suggests 2 different answers depending on where the initial point are taken?
eazyasshow do i find the conjugacy classes of S3?
TRWBWeazyass: start with the definitons
qqexdelta: i'm not sure that it does. the points only need be interior to the disk. it seems no matter how i look at, it's a circle. it could very well be...
TRWBWeazyass: what the conjugacy relation?
eazyassall elements b = x^-1*a*x for a,b, x elements of G
TRWBWeazyass: and have you show that it's an equivalence relation?
deltaqqex, I'd retract X to the circle in a few steps. We can try and see if it makes any sens to you.
eazyassit's given to us as one
Syzygy-qqex: Identifying two interior points'll be homotopic to inserting a 1d handle connected to those points.
TRWBWeazyass: um, that's not how it works
_llll_conjugacy in S_n is just the cycle type (rigth?)
TRWBWeazyass: do you know the definition of an equivalence relation? you actually *prove* it
_llll_: yes, but i don't think that's the most helpful thing here, seems like eazyass is just starting on this
_llll_huh?
did i misunderstand the question, or did you?
TRWBW_llll_ i figure they probably want him to do S3 by hand and then lead into proving the general case
qqexsyzygy: i follow you, though i don't know the significance of that.
Syzygy-_llll_: Yeah, it is. And this is why you want Young diagrams when studying the symmetric groups.
TRWBW_llll_: but that's just my opinion

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