yi | ah i see what you mean |

raz0 | TRWBW, So to solve f'(x)==0, I have use the power rule for ln, but how do I get rid of the 2 in 2*exp(..? |

TRWBW | raz0: what did you get for f'(x) again? 2e^(-(2x)^2)-e^(x^2)? |

raz0 | Yes |

TRWBW | raz0: multiply by e^(x^2). move the 1 to the other side. take logs oops raz0: what did you get for f'(x) again? 2e^(-(2x)^2)-e^(-x^2)? ( -x^2 not x^2) |

raz0 | er yes, of course. :) Doh. Of course. I feel stupid for not seeing that now, hah. Oh well. it's late. :) |

TRWBW | raz0: no blood, no foul |

eyie | how do i determine the sum of x^(2k+1) / (k(2k+1)), k=1 -> oo, |x| <= 1? |

Kasadkad` | eyie: Note the 2k+1 in both the exponent and the denominator Remind you of anything? |

eyie | not really. i'm brushing up on some math i did way back |

Kasadkad` | heh Well What happens when you take the derivative of that series? |

TRWBW | haha eyie: waht Kasadkad` said. |

eyie | TRWBW: how was that funny? |

TRWBW | eyie: i was funny because i was typing in a long explanation then saw that Kasadkad` had said the key point |

eyie | oh well. yeah.. so.. i can get something like x^2^k / k which i guess has something to do with ln (1 - x), but i dont really know how to progress from there |

TRWBW | eyie: well start with u=x^2 in x^(2k) eyie: if you've gotten that, i don't know what more you expect |

eyie | how do i determine the constant? |

TRWBW | ? eyie: you need to integrate ln(x) at some point for the constant, well x=0 -> 0 |

eyie | too tired to think straight right now. could you write it out for me so i have something to contemplate when getting ready for bed? |

raz0 | TRWBW, Just want to thank you. Got it all now. Much appreciate the help. :) |

TRWBW | eyie: i think you got all the main points. differentiate, substitute, relate to log, integrate, solve for the constant by f(0)=0 raz0: np |

gxmzack-sleep | anyone have a sec? |

TRWBW | okay, but damn, that was the second. |

gxmzack-sleep | ahh crap thanks anyways 4(x - 4)/(x +4)(x - 4)(x -4) - 3(x + 4)/(x +4)(x - 4)(x -4) it looks nicer on paper :( |

evilMan | can i have a question, Exp(risk) = Est(dam) * Prob(mat), i have value of Est(dam) and Pro(mat) and Exp(risk), The question asking is Deermine the priorities of Exp(risk) using only Est(dam) parameter, |