#math - Thu 1 Mar 2007 between 15:26 and 15:39

NY Lost Funds



tom2342344*about how
cskoTRWBW: im trying to understand what you say
tryied to solve that equation system with no success
TRWBWcsko: well the two operations are analgous to the gcd operations, and it terminates when you get some final f'=d
frobozz_don't you mean the euclidean algorithm for gcd?
TRWBWfrobozz_: i do
cskoi think i know what you are talking about now
TRWBWcsko: really they alternate, so you could just make it f'=1/(1+(b-a)/a))
albackerguys n/(n+2) - (1-n)/(1+n) is positive or negative for n>=0
TRWBWalbacker: do it out, just like any other fraction subtraction
johnDoe2It has the same sign als n(n+1)-(1-n)(n+2)
cskopositive for n>-1/2+1/2*5^(1/2)
johnDoe2Therefore it's possitive
cskofor 0 its -1
johnDoe2The term is negative only for n=1. And positive for all n greater than 0
for n=0*
de1337@mbot: 2+2
mbotde1337: 4
de1337@mbot: 1/2(E^(I*14) + E^(-I*14)) // N
mbotde1337: 0.1367372182078336 + 0.*I
de1337@mbot: Cos[14] //N
mbotde1337: 0.1367372182078336
spaceinvadermbot: % Solve[x^2-2x-5==0,x]
@mbot: % Solve[x^2-2x-5==0,x]
mbotspaceinvader: {{"No state is preserved between computations, so % doesn't work."*(x -> 1 - Sqrt[6])}, {"No state is preserved between computations, so % doesn't work."*(x -> 1 + Sqrt[6])}}
frobozz_@mbot: 4*atan[1]
mbotfrobozz_: 4*atan[1]
spaceinvader@mbot: % Solve[x^2-2*x-5==0,x]
mbotspaceinvader: {{"No state is preserved between computations, so % doesn't work."*(x -> 1 - Sqrt[6])}, {"No state is preserved between computations, so % doesn't work."*(x -> 1 + Sqrt[6])}}
spaceinvader@mbot: Solve[x^2-2*x-5==0,x]
mbotspaceinvader: {{x -> 1 - Sqrt[6]}, {x -> 1 + Sqrt[6]}}
frobozz_@mbot: 4*Atan[1]
spaceinvaderhah
mbotfrobozz_: 4*Atan[1]
frobozz_ugh.
de1337@mbot: 4*ArcTan[1] //N
mbotde1337: 3.141592653589793
de1337@mbot: 4*ArcTan[1] == Pi
mbotde1337: True
spaceinvader@mbot: Solve[(2+Sqrt[3](5-Sqrt[3]== a + b Sqrt[3],ab]

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