|eduardo||well if so, i have a proof. I think|
|Olathe||If Wikipedia is right.|
|eduardo||Cauchy are you there? I think i figured it out|
|eduardo||Cauchy, I think it's easy. ||X - Xo|| <= r is a subset of R^d, right?|
therefore the VC-D of this is less than the VC-D of R^d
|Cauchy||you're looking for the dimension of the class of those sets..|
you're supposed to use lemma 15, i guess..
|eduardo||Cauchy: but I think it still holds...|
say Z is the set of all closed balls in R^d
VC-D < VC-D(R^d)
Cauchy: I think I am done
or u really dont think so
|Phylo||how can I solve Integral[(x^2 + x)/Sqrt[x+1], x]? it's using substitution somehow|
I broke it into Integral[x/Sqrt[x+1], x] and Integral[(x+1)/Sqrt[x+1], x], but I don't know how to solve the first
oooh, that algebra is wrong isn't it...
I might be back, but until then, nvm, goodbye
|joblot||Phylo : x+1->y, so y-1/root(y), then \int root(y)-1/root(y)|
anybody knows how to represent this function ? x=-y^2/2 + 4
|Axsuul||Anyone know circuit analysis fairly well?|
|joblot||Godfather: wenn si vollen, y'' = - y^2 ... ist ln x verlantelen|
|Olathe||f(y) = -y^2/2 + 4 looks good.|
-y^2/2 + 4 - x = 0, which allows you to find y.
|Godfather||Olathe, -y^2/2 + 4 - x = 0|
how to represent that function?
Olathe, if i put y = 0 i find x= 4
and x = 0 -> y=(8)^1/2
|joblot||Godfather : basic x = y^2, its a parabola, factor y^2 = 2(x-4), again a parabola|
|Godfather||i know, but i only find 2 points, (4,0) and (0,8^1/2)|
joblot, any ideas?
|joblot||y=0, x=4; y=1, x=1/2 + 4|
|Axsuul||If anyone is familiar with circuits, I am confused as to what V' would be in this image: http://www.vega.org.uk/video/subseries/8|
oops wrong link