| Andriel | BnN puts ahahahahaha |
| TRWBW | okay, take the triangle ACE |
| |Anubis | good luck |
| Andriel | BnN faz a distncia de ponto a reta! ops distncia entre 2 pontos. |
| TRWBW | Andriel: don't taunt the happy fun ball BnN: you want me to explain this to you or not? |
| BnN | yup |
| TRWBW | okay, take the triangle ACE |
| BnN | i wanna see how you will do it ok |
| TRWBW | what's the angle at E? |
| Andriel | d(O,A) = d(O,B) sqrt{[(5-x(a))^2] + [(-6-y(a))^2]} = 6 |
| BnN | pi/2 |
| Andriel | 25 - 10x(a) + [x(a)^2] + 36 + 12y(a) + [y(a)^2] = 36 [x(a)^2] + [y(a)^2] - 10x(a) + 12y(a) = -25 |
| TRWBW | okay, and what's the length AE? |
| BnN | 5 |
| Andriel | [x(a)^2] + [y(a)^2] = 25 <=> circ. |
| TRWBW | and the length AC? |
| Andriel | [x(a)^2] + [y(a)^2] - 10x(a) + 12y(a) = -25 -> -10x(a) + 12y(a) = -50 12y(a) = 10x(a) - 50 y(a) = x(a)6/5 + 5 ops 12y(a) = 10x(a) - 50 |
| BnN | i don`t know |
| Andriel | y(a) = x(a)5/6 + 25/6 x(a) = y(a)6/5 + 5 |
| BnN | oh, wait |
| Andriel | (y^2)36/25 + 12y + 25 + y^2 = 25 (y^2)61/25 + 12y = 0 |
| BnN | just a second |
| TRWBW | you know C is at (5,-6) and A is at (0,0), what's the length of AC? |
| BnN | done TRWBW well.. the leght AC is... |
| TRWBW | okay, doesn't matter the exact number |